Engineering Economy – Problem 2.65
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Engineering Economy – Problem 2.65

An investment of $75,000 in equipment that will reduce the time for machining self-locking fasteners will save $20,000 per year. At an interest rate of 10% per year, the number of years required to recover the initial investment is closest to: (a) 6 years(b) 5 years(c) 4 years(d) 3 years Sample problems and notes are…

Engineering Economy – Problem 2.60
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Engineering Economy – Problem 2.60

A small construction company is considering the purchase of a used bulldozer for $61,000. If the company purchases the dozer now, the equivalent future amount in year 4 that the company is paying for the dozer at 4% per year interest is closest to: (a) $52,143(b) $65,461(c) $71,365(d ) Over $72,000 Sample problems and notes…